杭电acm部分题目及答案答案

杭电acm部分题目及答案答案杭电acm部分题目及答案答案自己刷的题这是我在杭电做题的记录，希望我的分享对你有帮助～～～ 1001 Sum Problem***********************************************************1 1089 A+B for Input-Output Practice (I)********************************2 1090 A+B for Input-Output Practice (II)******************...

杭电acm部分题目及答案答案自己刷的题这是我在杭电做题的记录，希望我的分享对你有帮助～～～ 1001 Sum Problem***********************************************************1 1089 A+B for Input-Output Practice (I)********************************2 1090 A+B for Input-Output Practice (II)********************************5 1091 A+B for Input-Output Practice (III)****************************************7 1092 A+B for Input-Output Practice (IV)********************************8 1093 A+B for Input-Output Practice (V)********************************10 1094 A+B for Input-Output Practice (VI)***************************************12 1095 A+B for Input-Output Practice (VII)*******************************13 1096 A+B for Input-Output Practice (VIII)******************************15 How to Type***************************************************************16 1001 Sum Problem Problem Description Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge). In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n. Input The input will consist of a series of integers n, one integer per line. Output For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer. Sample Input 1 100 Sample Output 1 5050 Author DOOM III 解答: #include main() { int n,i,sum; sum=0; while((scanf("%d",&n)!=-1)) { sum=0; for(i=0;i<=n;i++) sum+=i; printf("%d\n\n",sum); } } 1089 A+B for Input-Output Practice (I) Problem Description Your task is to Calculate a + b. Too easy?! Of course! I specially designed the problem for acm beginners. You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim. Input The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line. Output For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input. Sample Input 1 5 10 20 Sample Output 6 30 Author lcy Recommend JGShining 解答: #include main() { int a,b; while(scanf("%d%d",&a,&b)!=EOF) printf("%d\n",a+b); } 1090 A+B for Input-Output Practice (II) Problem Description Your task is to Calculate a + b. Input Input contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line. Output For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input. Sample Input 2 1 5 10 20 Sample Output 6 30 Author lcy Recommend JGShining 解答: #include #define M 1000 void main() { int a ,b,n,j[M],i; //printf("please input n:\n"); scanf("%d",&n); for(i=0;i main() { int a,b; scanf("%d %d",&a,&b); while(!(a==0&&b==0)) { printf("%d\n",a+b); scanf("%d %d",&a,&b); } } 1092 A+B for Input-Output Practice (IV) Problem Description Your task is to Calculate the sum of some integers. Input Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed. Output For each group of input integers you should output their sum in one line, and with one line of output for each line in input. Sample Input 4 1 2 3 4 5 1 2 3 4 5 0 Sample Output 10 15 Author lcy Recommend JGShining 解答: #include int main() { int n,sum,i,t; while(scanf("%d",&n)!=EOF&&n!=0) { sum=0; for(i=0;i main() { int n,a,b,i,j,sum; sum=0; while(scanf("%d\n",&n)!=-1) { for(i=0;i main() { int n,a,b,i,j,sum; sum=0; while(scanf("%d\n",&n)!=-1) { for(j=0;j main() { int a,b; while(scanf("%d%d",&a,&b)!=EOF) printf("%d\n\n",a+b); } 1096 A+B for Input-Output Practice (VIII) Problem Description Your task is to calculate the sum of some integers. Input Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line. Output For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs. Sample Input 3 4 1 2 3 4 5 1 2 3 4 5 3 1 2 3 Sample Output 10 15 6 Author lcy 第 15 页共 20 页杭州电子科技大学acm习题精选 Recommend JGShining 解答: int main() { int a,b,i,j,l[1000],k; scanf("%d",&i); getchar(); for(j=1;j<=i;j++) l[j]=0; for(j=1;j<=i;j++) { scanf("%d",&a); getchar(); for(k=1;k<=a;k++) { scanf("%d",&b); getchar(); l[j]+=b; } } for(j=1;j<=i-1;j++) printf("%d\n\n",l[j]); printf("%d\n",l[i]); } How to Type Problem Description Pirates have finished developing the typing software. He called Cathy to test his typing software. She is good at thinking. After testing for several days, she finds that if she types a string by some ways, she will type the key at least. But she has a bad habit that if the caps lock is on, she must turn off it, after she finishes typing. Now she wants to know the smallest times of typing the key to finish typing a string. Input The first line is an integer t (t<=100), which is the number of test case in the input file. For each test case, there is only one string which consists of lowercase letter and upper case letter. The length of the string is at most 100. Output For each test case, you must output the smallest times of typing the key to finish typing this string. Sample Input 3 第 16 页共 20 页杭州电子科技大学acm习题精选 Pirates HDUacm HDUACM Sample Output 8 8 8 第 17 页共 20 页杭州电子科技大学acm习题精选 #include #include #define MAX 200 int arr[MAX][4]; char str[MAX]; int letter(char ch) { if(ch>='A'&&ch<='Z') return 1; return 0; } void proc() { int i; int tmp,min; int len=strlen(str); for(i=0;iarr[i-1][2]+1||!arr[i][0]) arr[i][0]=arr[i-1][2]+1; if(arr[i][3]>arr[i-1][2]+3||!arr[i][3]) arr[i][3]=arr[i-1][2]+3; } if(arr[i-1][3]) { if(arr[i][1]>arr[i-1][3]+2||!arr[i][1]) arr[i][1]=arr[i-1][3]+2; if(arr[i][2]>arr[i-1][3]+2||!arr[i][2]) arr[i][2]=arr[i-1][3]+2; } } else { if(arr[i-1][0]){ arr[i][1]=arr[i-1][0]+2; arr[i][2]=arr[i-1][0]+2;} if(arr[i-1][1]){ arr[i][0]=arr[i-1][1]+1; arr[i][3]=arr[i-1][1]+3;} if(arr[i-1][2]) 第 18 页共 20 页杭州电子科技大学acm习题精选 { if(arr[i][1]>arr[i-1][2]+2||!arr[i][1]) arr[i][1]=arr[i-1][2]+2; if(arr[i][2]>arr[i-1][2]+2||!arr[i][2]) arr[i][2]=arr[i-1][2]+2; } if(arr[i-1][3]) { if(arr[i][0]>arr[i-1][3]+1||!arr[i][0]) arr[i][0]=arr[i-1][3]+1; if(arr[i][3]>arr[i-1][3]+3||!arr[i][3]) arr[i][3]=arr[i-1][3]+3; } } } } min=3*MAX; if(letter(str[len-1])) { if(arr[len-1][0]){ tmp=arr[len-1][0]+1; if(tmp

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杭电acm部分题目及答案答案

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