生产运营管理在线作业答案

生产运营管理在线作业答案 下述项方法项品出项项中的具项品的需求项化项成项品的零哪将划体构1. 部件和原材料的需求, • 粗略能力项 划A • 物料需求项 划B • 能力需求项 划C • 项存项 划D 正答案确:B 项项项 分析包括,2.SWOT • 外部分析,项项机和威项 会A • 内部分析,项项项项和劣项 B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 提出不同项合下的策略 C • 以上都包括 D • 以上都不是 E 正答案确:D 项项项 制定生项大项需要多项项入～项项入自企项外部,哪来3.• 项有项存水平 A • 原材料供项能力 B • 项有项工量 数C • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime 项有项项能力 D • 项工技项水平 E 正答案确:B 项项项 项公司的项的方向和基本特点起作用的项略是,4.• 项期的 A • 中期的 B • 短期的 C • 项项的 D • 以上都不是 E 正答案确:A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 项项项 项项序列据可能 表 关于同志近三年现实表现材料材料类招标技术评分表图表与交易pdf视力表打印pdf用图表说话 pdf 项项,数5.• 项项 A • 季项波项 B • 周期波项 C • 不项项波项 D • 以上所有的 E 正答案确:E 项项项 哪项是公司项略,6.• 成本项先 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • 差化 异B • 集中化 C • 多元化 D • 以上都不是 E 正答案确:D 项项项 企项项造的价项是,7. • A V • B V-P • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twervel?te?y?respectfiimeantime C V-C • D P-C • 以上都不是 E 正答案确:C 项项项 哪项是事项部项略,8. • 相项多元化 A • 不相项多元化 B • 垂直一化 体C • 水平一化 体D he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime • 成本项先 E 正答案确:E 项项项 下列一项是项品和服项项项项准化的缺点,哪9. • 增加项存品项 数A • 增加培项项用 B • 减少项项项用 C • 减少项品多项性 D • 以上都是 E 正答案确:D 项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 项项,10.• 项项比项项的更准 确A • 项项项项品的项项比整项目的更准 体B • 是不完美的 C • 以上都项 D • 以上都不项 E 正答案确:C 项项项 下列项不是生项作管理的目项,哪运11.• 高效 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • 灵活 B • 准项 C • 清项 D • 以上都不是 E 正答案确:E 项项项 下项不于大量生项作,来哪属运12.• 项机制造 A • 汽项制造 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime 快餐 C • 中小育 学教D • 学学体生入项 E 正答案确:A 项项项 项项能助项理,帮13.• 项项未 来A • 项生项系项的项展项行项 划B • 项生项系项的使用项行项 划C • 以上都是 D he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • 以上都不是 E 正答案确:D 项项项 当会况供不项求项～出项下述情,14.• 供方之项项激化 争A • 价格下跌 B • 出项回项项象 C • 项量和服项水平下降 D • 项量少 减E 正答案确:D 项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 按照生项要素密集程度和项客接程度分～院是,与触划医15.• 大量项本密集服项 A • 大量项项密集服项 B • 项项项本密集服项 C • 项项项项密集服项 D • 以上都不是 E 正答案确:C 项项项 人机工程究的工作项境不包括一项,研哪16.• 气状况候 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • 照明色彩 与状况B • 噪声与状况振项 C • 人项项系 状况D 正答案确:D 项项项 在生项大项定后～一般项～项接着项行项活项,确来哪17.• 流程 快递问题件怎么处理流程河南自建厂房流程下载关于规范招聘需求审批流程制作流程表下载邮件下载流程设计 项项 A • 制项项略性的能力项 划B • 项制项品出项项 划C • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 项制物料需求项 划D 正答案确:C 项项项 商项不等于项项～是因项,18.• 要项项项项手 争A • 要用项略 运B • 要项市项项 争份C • 既争要项又要合作 D • 以上都是 E 正答案确:D 项项项 用于高度项准化项品的加工系项是,19.he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 流水项式项项的 A • 项的 断B • 项目式的 C • 批量的 D • 项件的 E 正答案确:A 项项项 哪项加工项型更适合多品项生项,20.• 装配项;, A assembly • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 项件小批生项;, B job-shop • 批量生项;, C batch• 项项生项;, D continuous • 项目;, E project 正答案确:B 项项项 做外包策项～公司要避免什项,决21. • 取消非核心项项 A • 提供机使得外包合作企项成项强有力项者 会争B • 允项雇项加入外包合作企项 C he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 允项外包合作企项项新项项 参与D 正答案确:B 项项项 下述项项用项合成了固定量项存系项的项项用,哪构22.• 年项项项、年项充项项项和固定项用 A • 年项持项存项、年项充项项项和项价 B • 年项持项存项、年项充项项项和年项项项 C • 年提前期项用、年项持项存项和年项项项 内D • 项价、年项整准项项和年项项项 E 正答案确:C 项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 下项项不是排序的项先项度法项,哪23.• 项先项项余下加工项项最项的工件 A • 项先项项加工项项最短的工件 B • 项先项项项界比项小的工件 C • 项先项项项界比项大的工件 D 正答案确:D 项项项 哪划项是项品出项项的项入,24.• 项存项文件 状A • 生项项大项 划B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • 项品项文件 构C • 项项生项作项项 划D 正答案确:B 项项项 项于福特汽项公司北美项项部项施的项法不正的是,确25.BPR • 项算机系项安起了最项项的作用 装A • 之前的多项项项理工作是一项浪项 很B • 重消除了项票项理 构C • 准性大大提高 确D 正答案确:A 项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 活项的最早可能项始项项是,26. • 项活项箭项事件的最早可能项生项项 A • 项活项的箭尾事件的最早可能项生项项 B • 项活项箭项事件的最项必项项生项项 C • 以上都是 D • 以上都不是 E 正答案确:B 项项项 一工件剩下个天加工项项～今天是项月的号个。如果项工件27.510 号到期～项界比是多少,14 • A 0.2 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • B 4 • C 1 • D 0.8 正答案确:D项项项 一多通道系项中～每小项项客的平均到是达数～平均服项项项项28.540 分项～项不项系项项项所需要的最小服项台是,数 • A 2 • B 3 • C 4 • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twervel?te?respecty?fiimeantime D 5 • 都不项 E 正答案确:C 项项项 某项零件的项需要量是由那一项定的,决29.• 项需要量 A • 项有 数B • 上项元件的项需要量 C • 上项元件的项项出项项量 划D • 所有以上因素 E 正答案确:D he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 项项项 制定生项大项项～下述项方法是正项的方法,哪数学30.• 反项项项法 A • 项性项 划B • 项表法 C • 模项法 D 正答案确:B 项项项 通项项可生项项任项最项落项到操作工人身上,哪将划31.• 流程项项 A • 能力项 划B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • 生项大项 C • 排序和项项生项作项项 划D 正答案确:D 项项项 哪属项项用不于项持项存项,32.• 保项 A • 利息 B • 缺项项失项 C • 项存照明 D • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime 项化项失 旧E 正答案确:C项项项 下面一项等于项客在系项中的平均项项,哪?系项中的平均除以数33.. 到率～达?系项中的平均乘以到率～数达?项列中的平均项项加上.. 平均服项项项。• 项? A • 项? B • ?和? C • ?和? D • 项? E 正答案确:C项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?book,?of?eteracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?he?a?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 以下项不于流程重的基本原项,哪属构34.• 尽个管项源被集中控制～但分散在多地方 A • 将并它活项行而不是项合项的项果 B • 在信息项生的地方多次采集信息 C • 将信息项理任项安排到项生信息的地方 D 正答案确:C 项项项 供项项管理下的采项项项与采项不同在于,35.• 项项存采项 A • 与供项商是一般项项项系 B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 与伙供项商项成项略伴项系 C • 项供项商项以项利 争D 正答案确:C 项项项 在项系项中～双个内第二项项的存项量项,36.• A RL • B EOQ • 安全存项量 C • 安全项存加上最佳项项批量 D • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 以上都不是 E 正答案确:A 项项项 流程重的原项之一,构37.• 从根源上保项项量 A • 由项流程项果项项的人项项项施 B • 不要项项根据价格项项供项商 C • 将非核心项项外包出去 D 正答案确:B 项项项 活项的最早可能完成项项是,38.• 项活项箭项事件的最早可能项生项项 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 项活项箭尾事件的最早可能项生项项 B • 项活项箭项事件的最项必项项生项项 C • 项活项箭尾事件的最早可能项生项项加上活项所需项项 D • 以上都不是 E 正答案确:D 项项项 事件项差是,39.• 最悲项和最项项项项之差 A • 项束项项和项始项项之差 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 事件最项项项和最早项项之差 C • 以上都是 D • 以上都不是 E 正答案确:C 项项项 下面一项不是哪模型的假项件,条40.EOQ • 年需求项已知的常量 A • 提前期已知且固定 B • 不允项缺项 C • 有量数扣折 D he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 项充率项无限大 E 正答案确:D 项项项 制定生项大项项～下述项方法是项项生项中项用最多的,哪41.• 项性策法项 决A • 项性项 划B • 反项项项法 C • 模项法 D 正答案确:C 项项项 哪会一项增加系项的使用率,42.• he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 服项率的增加 A • 到率的增加 达B • 服项台的增加 数C • 服项项项的少 减D • 以上各项均可 E 正答案确:B 项项项 项目管理主要是控制,43.• 项量 A • 项度 B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 成本 C • 以上都是 D • 以上都不是 E 正答案确:D 项项项 在制定项存量的策项～不需决哪考项下述项项用,44.• 项持项存项 A • 项整准项项 B • 项项项 C • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime 固定成本 D • 缺项项失项 E 正答案确:D 项项项 下述项不于项持项存项,哪属45.• 物料项用 A • 运项项 B • 保项项 C • 被项失 盗D • 项项项施折旧 E 正答案确:B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项项项 供项项项项项是项项项准的响哪衡量,46.• 系项的可性 靠A • 柔性 B • 项项利用率 C • 项品项量 D 正答案确:D 项项项 在排项分析中～下面一项通哪当常不被做系项项效的度量,47.• 等待项列中的平均人 数A • 系项中的平均人 数B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 系项的使用率 C • 服项台的项用加上项客的等待项用 D • 服项项项 E 正答案确:E 项项项 下面那一项不是项持项存的原因,48.• 使生项系项平项行 运运A • 减少缺项项项 B • 使生项活项准项项行 C • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 减少项项项 D • 防止短缺 E 正答案确:C 项项项 供项项的项成包括,49.• 供项商 A • 项客 B • 内部供项项 C • 以上都是 D 正答案确:D 项项项 与流水项项排序不直接相项的是,50.he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 加工描述矩项 A • 加工项项矩项 B • 加工项序矩项 C • 漏斗”模型 D “ 正答案确:D 项项项 以下一是项目的特点,哪条51.• 一次性 A • 重项 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项出项准的 C • 重项性工作多 D • 项项小 E 正答案确:A 项项项 相项于～用范项作项控制项项出项第?项和?项项项的影响是,52.2σ3σ • 同项少项项项项生的率 减两概A • 同项增加项项项项生的率 两概B • 增加?项项项项生的率～同项少概减?项项生的率 概C • 增加?项项项项生的率～同项少概减?项项项项生的率 概D he?n?twatch.?he?actthe?Tomb,?news?Ito?masses??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?n?seriea,Tomb?ar?wriion?twer?tvele?y?respectfiimeantime • 项项项项项生率什项两概没响影 E 正答案确:D 项项项 项项项合工程的特点不包括下述一项,学哪53.• 以项项的整个寿研命周期作项管理和究的项象 A • 将寿研项项最项项的命周期项用作项究目的 B • 强项全面的、项合的管理 C • 强项项项的项项、使用和项用的信息反项 D • 强项最高项项到从体参第一项工人全成项的加 E 正答案确:E 项项项 he?n?twatch.?he?the?Tomb,?news?Ito?masses?act?ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?eracy?tetbook,?ed?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?n?seriea,Tomb?ar?wriion?twer?tvele?y?respectfiimeantime 按照项束理项～以下一项是哪衡量企项项项能力的项项指项,54.• 项售收入 A • 项项率 B • 项利项 C • 项存 D • 其他收入 E 正答案确:C 项项项 以下一项不是小批量的哪好项,55.• 在制品项存量低 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?n?seriea,Tomb?ar?wriion?twer?tvele?y?respectfiimeantime • 每项项品生项的项数低 B • 项持项存项低 C • 项项和返工的成本低 D • 物料流项快 E 正答案确:B 项项项 下述一项不是项量管理的项项控制方法,哪56.• 数据分项法 A • 排列项 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项项分析表 C • 直方项 D • 漏斗模型 E 正答案确:E 项项项 以下一项不是哪“活项的一部分,57.5s” • 整理 A • 整项 B • 清项 C • 清项 D he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 操项 E 正答案确:E 项项项 全面生项项修制的主要内哪容不包括下述一项,58.• 日常点项 A • 项项划修、改善性项修、故障修理三项机制相项合 B • 项修项项分析 C • 抽项项项分析 D • 项展活项、项常项行全面生项项修制的育 教E 5S 正答案确:D 项项项 he?n?twatch.?he?the?Tomb,?news?Ito?masses?act?ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Maplng?l?Japanese?antoftiomb?ounded?progressive?youth?orcampaies??t"Youth?Clganign.iub",zatof??They?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 以下不于哪条属的条原项,59.OPT9 • 项批量可以不等于加工批量 运A • 瓶项控制了项存和项项率 B • 平衡物流～而不是平衡能力 C • 瓶它决决项项源的利用程度不是由本身定的～而是由其他项源定的 D • 瓶项上小项的项失就是整系项个小项的项失 E 11 正答案确:D 项项项 项量管理使用的分析工具有下述一项,哪60. • 项项 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?emented?ustides,?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?ng?lantoftiomb?ounded?progressive?youth?orcampai?t"Youth?Clganign.ies?ub",of?zat?They?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime • 不断改项 B • 快速响项 C • 建立伴伙项系 D • 排列项 E 正答案确:E 项项项 精项生项的内容不包括,61.• 项品精项 A • 布置精项 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项项精项 C • 管理项项化 D • 项程精项 E 正答案确:D 项项项 全面生项项修制的基本思想不包括下述一项,哪62.• 全效率 A • 全系项 B • 全项程管理 C • 全社推会项 D he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 全项 参与E 正答案确:D 项项项 以下项不是流程管理的特点,哪63.• 追求企项管理的项项化和高效化 A • 从项果出项倒退项程 B • 全流程项点代替个项部项的活项 C • 内部作项方便便是流程管理的出项点 D 正答案确:D 项项项 以下项不是服项作的特点,哪运64.• he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?book,?of?eteracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?he?a?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 生项率项以定 确A • 项量项准项以建立 B • 服项项程可以消项项程分 与离C • 项服项不能通项项存项项 D • 与触项客接 E 正答案确:C 项项项 低项策被项,决称65.• 项略策 决A • 项项策 决B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 操作策 决C • 项项 D • 项项策 决E 正答案确:C 项项项 在大多企项中存在的数三项主要项能是,66.• 制造、生项和作 运A • 运作、项项和项项 B • 运作、人事和项项 C • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 运作、制造和项项 D • 以上都不是 E 正答案确:B 项项项 按照物流特征～项机制造企项于,属67.• 型企项 A A• 型企项 B V• 型企项 C T• 以上都是 D • 以上都不是 E 正答案确:A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项项项 相项于流程式生项～加工配式生项的特点是,装68. • 品项项多 数A • 项本密集 B • 有项多项准项品 C • 项项柔性项低 D • 只能停项项修 E 正答案确:A 项项项 假定无需安全项存～某项品的平均日消耗量项件～提前期项69.3010 天～项有项存量项件～项项点是多少,500 • he?n?twatch.?he?actthe?Tomb,?news?Ito?masses??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miitilwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twervel?te?y?respectfiimeantime A 200 • B 300 • C 400 • D 500 • E 600 正答案确:B项项项 哪项行项最适合,70.MPR • 机床厂 A • 医院 B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime • 造项 厂C • 项油厂 D 正答案确:A 项项项 下述一项包括项品在加工项程中的作项项项项,哪71.• 项品的基本工作项项和无效项项 A • 项品的基本工作项项和项放项项 B • 项品的基本工作项项和项整准项项项 C • 项品的基本工作项项和项品项项缺陷的工项消耗 D 正答案确:A 项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 制定生项大项～项方式是准项生项的哪梦想,72.• 改项生项率～使之需求同与步 A • 推项交项 B • 改项项存水平 C • 即改项项存水平～又推项交项 D • 项包 E 正答案确:A 项项项 两个一般的项项方法是,73.• 数学的和项项的 A he?n?twatch.?he?the?Tomb,?news?Ito?masses?act?ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?eracy?tetbook,?ed?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?n?seriea,Tomb?ar?wriion?twer?tvele?y?respectfiimeantime • 定性的和定量的 B • 判断的和定性的 C • 项史的和相项的 D • 判断的和相项的 E 正答案确:B 项项项 哪一项不是相项需求,74.• 原材料 A • 在制品 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 成品 C • 外项零件 D • 项品项明项 E 正答案确:C 项项项 研与哪究项项是指如下些活项,?基项究 研?项用究 研?将项用75.... 研究的成果项化项商项上的项用 • ?A • ?和? B • ?和? C • ?和? D he?n?twatch.?he?the?Tomb,?news?Ito?masses?act?ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miitilwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twervel?te?y?respectfiimeantime • ?、?和? E 正答案确:E 项项项 和的主要不同点是,76.MRPDRP • 假项能力无限 A • 固定提前期 B • 按项段项项 C • 自上而下项理 D 正答案确:D 项项项 下列一项不是哪断主项判的项项方法,77. • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?n?seriea,Tomb?ar?wriion?twer?tvele?y?respectfiimeantime 主管的意项 A • 项项售伍的意项 B • 消项者项项 C • 德项菲方法 D • 项项序列分析 E 正答案确:E 项项项 以下项不是哪的项入,78.MRP • 生项大项 A • 项品出项项 划B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 项品项文件 构C • 项存项文件 状D 正答案确:A 项项项 供项项成项项缺乏同步性的项果是,79.• 提前项项 A • 持项项充 B • 牛鞭效项 C • 项项效项 D 正答案确:C 项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 求机型项存项项的项项点项～除了项算提前期需求的期随内望项外～项80. 需加上下述一项,哪 • 需求的均项乘提前期的项准差 A • 项乘提前期 B Z • 需求的项准差乘提前期的项准差 C • 提前期乘提前期的项准差 D • 提前期需求量的项准差乘内项 E Z 正答案确:E 项项项 制定生项大项需要多项项入～项项入自企项部,哪来内81. • 项包商能力 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 市项需求 B • 项有项项能力和项工量 数C • 项者行项 争D • 原材料供项能力 E 正答案确:C 项项项 固定量存项系项的基本模型不包括下述项哪假项,82.• 一次项项项或项整准项项是常量 A • 根据平均项存项算项持项存项 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项存回项是项存的减数函 C • 提前量项常量 D • 需求率均匀且项常量 E 正答案确:C 项项项 用于生项项项的、有特殊要求的一次性项品的加工系项是,83.• 流水项式项项的 A • 项的 断B • 项目式的 C • 批量的 D he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 项件的 E 正答案确:C 项项项 项项是以下活项的依据,84.• 能力项 划A • 项算 B • 项项项 售划C • 制造项 划D • 以上都是 E 正答案确:E 项项项 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项项工作方式的特点和要求不包括下述一项,哪85.• 工作人项高素项～多技能 A • 项多的只能工作内容 B • 基项自主性强 C • 众从属多的项系 D 正答案确:D 项项项 项项路项是,86.• 活项最多的路项 A • 项点最多的路项 B he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime • 项项最项的路项 C • 将来项项项差项零的项点项接起的路项 D • 以上都是 E 正答案确:C 项项项 按照项束理项～以下一项是哪衡量企项盈利能力的作项指项,87.• 项售收入 A • 项项率 B • 运行项 C • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?book,?of?eteracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?he?a?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 项位成本 D • 项存 E 正答案确:B 项项项 哪条一项不是项项准项生项的件88. • 减少项整准项项项 A • 准项采项 B • 建立推项式系项 C • 从根源上保项项量 D • 建立“型生项项元 E U” 正答案确:C he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项项项 下述一项不是项量管理使用的分析工具,哪89.• 因果分析项 A • 甘特项 B • 散布项 C • 控制项 D • 直方项 E 正答案确:B 项项项 下述一项是项量管理的项项控制方法,哪90.• 项项 A he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • 控制项 B • 不断改项 C • 看板 D • 箭项型项项 网E 正答案确:B 项项项 下述一项方法不于项项哪属划防修理制的方法,91.• 项准修理法 A • 定期修理法 B • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriwerion?t?tvele?y?respectfiimeantime 项项后修理法 C • 项目修理法 D 正答案确:D项项项 任项分派情下～况个工件分派项台机器上有多少项不同方法,92.55 • A 5 • B 25 • C 120 • D 3125 正答案确:C项项项 一项通路排项系项的平均服项项项是分项～平均到项项是达分项～93.810 到率项,达 he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?emented?ustides,?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?ng?lantoftiomb?ounded?progressive?youth?orcampai?t"Youth?Clganign.ies?ub",of?zat?They?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime • 次每小项 A 6/• 次每小项 B 7.5/• 次每小项 C 8/• 次每小项 D 10/• 次每小项 E 5/ 正答案确:A 项项项 项什项在无限源排项系项中有等会待,94.• 安排欠妥当 A • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?book,?of?eteracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?ounded?progressive?youth?oroftiomb?campaiant?t"Youth?Clganign.ies?ub",zat?They?of?he?a?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 服项太慢 B • 使用率太低 C • 到率服项率不项定 达与D • 多项段项理 E 正答案确:D 项项项 从概念上项～可做到,95.JIT • 工件在加工项程中有等没待 A • 没有无事可干的工人 B • 没有等待零件加工的机器 C he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?emented?ustides,?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?ng?lantoftiomb?ounded?progressive?youth?orcampai?t"Youth?Clganign.ies?ub",of?zat?They?a?he?seriea,Tomb?arn??wriion?twer?tvele?respecty?fiimeantime • 项项里没有项存 D • 以上各项 E 正答案确:E 项项项 项项项项的基本策有决哪些,96.• 集中项修与分散项修的项项 A • 委托项修与自行项修的项项 B • 项用项项项项和更项年限决策 C • 项防性项修与确项候项理的项项～以及项修人项的定 D • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?emented?ustides,?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Maplng?l?Japanese?antoftiomb?ounded?progressive?youth?orcampaies??t"Youth?Clganign.iub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime 以上全部 E 正答案确:E 项项项 哪一项是项束理项项项的一步,97. • 项项项 瓶A • 减少系项的项束 B • 强化系项项束 C • 支持系项项束 D • 若没个有系项项束～制造一项束 E 正答案确:A 项项项 一排项系项有个个个小项～每小项包含个数成项～服项台的量项,98.43 he?n?twatch.?he?the?Tomb,?news?Ito?masses?act?ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Maplng?l?Japanese?antoftiomb?ounded?progressive?youth?orcampaies??t"Youth?Clganign.iub",zatof??They?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime • A 3 • B 4 • C 7 • D 12 • E 1 正答案确:B 项项项 无限源有与区限源排项模型的基本项是,99.• 服项台的量 数A • he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?omb?oftiounded?progressive?youth?orcampaiant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twervel?te?respecty?fiimeantime 平均等待项项 B • 到率的分达布 C • 潜在呼叫人口的项模 D • 加工项理速率 E 正答案确:D 项项项 哪属构项不于流程重的方法,100. • 借助咨项公司的力量 A • 项项思项模式、改造公司文化 B • 借助信息技项 C he?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antic?n?publiextpostshing?of?etbook,?eracy?ted?miilitwrion?meographed?Bulhe?Mapl?Japanese?lng?campaioftiomb?ounded?progressive?youth?orant?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twervel?te?y?respectfiimeantime • 从不项项的项项项项入手 D 正答案确:Dhe?n?twatch.?he?Ito?masses?actthe?Tomb,?news??ttrsupplof?ce,?ementdes,ed?usti?Japanese?songs??ate?siby?comithe?jand?te?antiextc?n?publipostshing?eracy?tof?etbook,?ed?miilitwrimeographed?Bulon?he?Mapllng??Japanese?oftiantomb?ounded?progressive?youth?orcampai?t"Youth?Clganign.ies?ub",zat?They?of?a?he?seriea,Tomb?arn??wriion?twer?tvele?y?respectfiimeantime