2013年哈尔滨市第三中学第二次高考模拟考试
数学
试卷
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(文史类)
一、选择题(本大题共12小题,每小题5分,共60分,在每小题给出的四个选项中,只有一项是符合题目要求的。)
二、填空题(本大题共4小题,每小题5分,共20分,将
答案
八年级地理上册填图题岩土工程勘察试题省略号的作用及举例应急救援安全知识车间5s试题及答案
填在答题卡相应的位置上.)
三、解答题(本大题共6小题,共70分,解答应写出文字说明,证明过程或演算步骤.)
请考生在第22、23、24三题中任选一题作答,如果多做,则按所做的第一题记分.
2013年哈尔滨市第三中学第二次高考模拟考试
数学试卷(文史类)答案及评分
标准
excel标准偏差excel标准偏差函数exl标准差函数国标检验抽样标准表免费下载红头文件格式标准下载
一、选择题:
题号
1
2
3
4
5
6
7
8
9
10
11
12
答案
B
A
B
B
B
C
C
D
C
B
C
D
二、填空题:
13.
14.
15.
16.
EMBED Equation.3
三、解答题:
17. (Ⅰ)整理得
……………………………… 4分
又
得
……………………………… 6分
(Ⅱ) 由(1)知
…………………………… 8分
所以
…………………………………… 12分
18. (Ⅰ) 第六组
···························2分
第七组
··························4分
估计人数为
··························6分
(Ⅱ) 设
组中三人为
;
组中两人为
则所有的可能性为
,
,
,
,
,
,
,
,
,
··························8分
其中满足条件的为
,
,
,
···················10分
故
··················· 12分
19.(Ⅰ)
EMBED Equation.3
,
分别为
的中点,
为矩形,
················· 2分
,又
面
,
面
,
平面
⊥平面
····················· 4分
(Ⅱ)
,又
,
又
,所以
面
,
,
面
··········6分
三棱锥
的体积
=
,到面
的距离
=
··········· 10分
可得
. ·············12 分
20. (Ⅰ)由已知
得
,
,方程为
···········3分
(Ⅱ)设
,则
(1)当直线
的斜率存在时,设方程为
联立得:
有
①
由以
为直径的圆经过坐标原点O可得:
·
整理得:
②
将①式代入②式得:
, ··········· 6 分
又点
到直线
的距离
·········· 8 分
所以
·········· 10 分
(2) 当直线
的斜率不存在时,设方程为
(
)
联立椭圆方程得:
代入
得到
即
,
综上:
的面积是定值
,
又
的面积
,所以二者相等. ········· 12 分
21. (Ⅰ)
,
···········1分
···········4分
(Ⅱ)由原式
令
,可得
在
上递减,在
上递增
∴
·········7分
即
·································8分
(Ⅲ)由(Ⅱ)知
在(0,1)上单调递减
∴
时,
即
·································10分
而
时,
··················11分
································12分
22.(I)∵
,∴
,
又∵
,∴
,∴
∽
∴
又∵
,∴
···5分
(II)
,
,
是⊙
的切线,
,
·······10分
23.(Ⅰ)圆
的极坐标方程为:
········· 5 分
(Ⅱ)圆心到直线距离为
,圆半径为
,所以弦长为
··········· 10分
24.(Ⅰ)
的解集为:
·········· 5分
(Ⅱ)
·········· 10 分
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