架空线路课程设计

题目：某110KV线路，通过我国U气象区，导线型号为LGJ-150/20,做出相关的应力弧垂曲线。?查出气象资料和导线参数1、整理U气象区的计算用气象条件，示于 表 关于同志近三年现实表现材料材料类招标技术评分表图表与交易pdf视力表打印pdf用图表说话 pdf 1-1中表1-1计算用气象条件最高气温最低气温最大风速覆冰年平均气温气温「C)40-1010-515风速(m/s)0030100冰厚(mm)000502、LGJ-150/20型导线的有关参数，汇集于表1-2中表1-2LGJ-150/20导线有关参数"面积A(mm)导线直径d(mm)弹性系数E(Mpa)膨胀系数a(1/C)计算拉断力(N)计算质量(kg/km)抗拉强度厅P(Mpa)安全系数k73000X10-646630?计算步骤1、计算架空线路比载名称符号计算公式结果自重比载丫1(0,0)/0,0)qg103Ax10-3冰重比载丫2(5,0)2(5,0)27.728b(db)103Ax10-3垂直总比载丫3(5,0)3(5,0)go)2(5,0)x10-3无冰风压比载丫4(0,30)AVV234(0,0)cfsdsin10Ax10-3覆冰风压比载Y5(5,10)八5,10=cfsc(d2b)AAsin2103Ax10-3无冰综合比载丫6(0,30)6(0,30)12(0,)42(0,30)x10-3覆冰综合比载Y7(5,10)7(5,10)32(5,)52(5,0x10-3计算架空线路比载(MPa/m自重比载坦549.49.80665164.510332.7510言1031(0,)冰重比载2(5,0)27.728呻10327.7285皿——164.55)10318.2610垂直总比载(5,0)i(0,0)2(5,0)=32.751018.2510351.01101.00.751.216.67062530210，51.31034(0,25)无冰风压比载scdWvsin2A103164.50.625102W,23'5(5,0=cfsc(d羽才sin1031.01.01.2(16.6725)10312.1610覆冰风压比载6(0,25)=12(0,0)42(0,25)(32.75103)2(51.3103)260.8310无冰综合比载覆冰综合比载7(5,10)=—52(5,1052.44102、确定应力值许用应力[(To]=4O%Cp=年均应力上限[Tcp]=25%Tp=3、确定临界档距，判定控制气象条件项目、、条件最大风速最厚覆冰最低气温年均气温许用应力[do](Mpa)比载Y(Mpa/m)x10-3x10-3x10-3x10-3Y/[do](l/m)x10-3X10-3x10-3x10-3温度t(C)10-5-1015Y/[do]由大到小编号ABDC4、计算临界档距当许用应力相等时代入公式h[」.当许用应力不相等时，代入公式24[o]j[o]iE(tjti)E([od[lad107.722419.610(1010)(60.86103)2(32.7510)203.68lab107.72292.86LACLBCLBD24[107.7267.3219.610。73000(1015)]73000[(0.565103)2(0.486103)2]24[107.7267.3219.610。73000(515)]73000[(0.487103)2(0.486103)2]2419.6106(510)(52.44107.72103)2(32.75103)127.5624[67.32107.7219.610。73000(1510)]LCD73000[(0.486103)2(0.304103)2]362.831995.42虚数逻辑图如当L＞时，A为控制气象条件（即最大风速）计算各气象条件的应力状态方程：。2离E2lf24020124oi6E73000,19.610(1)最高气温CT01=(①L=50丫2=x10-312=40rt1=15°C7300062.75103)2500222402解得02=36.032)L=100丫2=x10-312=40Ct1=15C7300062.7510)1002240267.327300十3275145019.610673000(4(15)、2467.32丫1=XCT10-301=67.327300切(32751T10019.61073000(405)2467.32解得02=42.4502解得t2=400Cti=15C73000(32.75103)2150240202=47.66L=200丫注x10-312=40Ct1=15C73000(32.75103)22000222402解得02=51.66L=250I2=x10-312=40Ct1=15C027300002.75103)22502402解得02=54.70L=300、2=x10_312=40Ct1=15C0273000(32.7510»30022402解得02=57.03L=350Y2=x10_373000(3275103)215067.322467.32-31=x10(T0167.32萩件冲02467.321=x10-367.3219.6106-619.61073000(4015)73000(4015)CT01=73000(327510322502467.3219.610673000(4015)_31=x10CT01=67.32I1=x10_373000(32.7510)23002467.32_619.610673000(4(15)CT01=0273000(32.7510)35。67.32^300(32751?35019.610。73000(4015)24022467.32解得02=58.83①L=丫2=x丫1=xCT10-310-301=t2=40°Cti=15°C7300062.7510)362.8302解得240202=59.23，73000(327510)磁曲诳诃67.3273000(405)6'.329L=400丫2=x10-3丫1=X10-3CT01一12=40Ct1=10C73000(32.7510)2400022402解得02=59.071077273000(6083103)240024107.7219.610673000(4010)10)L=450Y2=x10-3丫1=x10(T01=12=40Ct1=10C73000(32.7510)4500222402…”7300(60831c450“107.72219.610673000(4010)24107.72解得02=58.86@L=500Y2=x10-31=x10-3CT0112=40Ct1=10C7300002.75103)250002202解得02=58.71107727600(608610^50024107.7219.610673000(4010)12L=55010丫1=x10CT0112=40Ct1=10C7300062.7510宇550022402107.7273004608310^55019.610673000(4010)24107.72解得02=58.5913)L=600丫2=x10-3-3Y1=x10(T01—t2=40°Ct=10°C73000(32.7510)6000224021077273000(608310)60024107.7219.610673000(4(10)解得02=58.50(2)最低气温1)L=50丫2=X10-3101=X-3CT01=02t2=-10Ct1—15C73000(32.7510)5022467.3273000(327510)502467.3219.61073000(1015)解得02=102.072=X10-3I1=X10-3(T01=02t2=-10Ct1=15C73000(32.7510)10067.322402“73000(327510)1002467.3219.610673000(1015)解得02=99.213L=150r2=x10-3CT01=t2=-10Ct1=15C730000272402Eg袖倒10673000(1015)解得02=95.02@■3L=200丫2=x10丫1=x10(T0273000(32.75103)22006732240273000(3275叮2002467.3219.61073000(1015)解得02=90.305L=250I2=X10-3Ii=X10-3CT01=t2=-10Ct1=15C73000(32.7510)25002240267.3273000(327510亍2502467.3^19.61073000(1015)解得02=85.806)L=300丫2=x10-3CT01=t2=-10Ct1=15C73000(32.7510)3000222402ccc73000(3275103)230067.3219.610解得02=81.997)L=350丫2=x10-3I1=X10-3(T01=022467.3273000(1015)t2=-10Ct1=15C73000(32.7510)3502240267.3273000(3275103)23502467.3219.61073000(1015)解得02=78.98I2=X10-31=X10-3CT01=t2=-10Ct1=15C73000(3275102402)2观曲67.3273000A327510^362>19.610673000(1015)2467.32解得02=78.33@L=400_32=X10_31=x10CT01=t2=-10Cti=1O°C73000(32.7510)40002解得2240202=74.6573000(608310)400107.72224107.72.Q19.610673000(1010)⑩L=450丫2=X10-3丫1=X10-3(T01=t2=-10Ct1=10C73000(32.7510)45002202240273000(6083103)2450107.72224107.72“619.610、73000(1010)解得02=70.95L=500丫2=X10-3丫1=X10-3(T01=107.727300千岫10i2-5ee19.610673000(1010)73000(32.75103)25000222402t2=-10Ct1=10C@L=550Y2=X解得02=68.3210-3丫1=X10-3(T202t2=-10Ct1=10C73000(32.75103)255(00222402解得02=66.41?L=600丫2=X10-373000(608310)255(0-6107.72219.61073000(1010)24107.72丫1=X10-3(T01=t2=-10Ct1=10C73000(32.75103)2600107.72呻冷吟公做19.610673000(1010)24107.72解得02=64.98(3)最大风速73000(60.8610)500222402解得02=77.38-3@L=100丫2=Xccc73000(3275103)25(f67.322467.32-3X1010(T01=t2=10Ct1=15C73000(60.8610)100022240267.32液曲(E蚪1002467.3219.610673000(105)解得02=83.45③L=150丫2=X10-3丫1=X10-3CT0102t2=10Ct1=15C73000(60.86103)215022402ccc73000(3275103)215067.322467.32-619.610673000(105)解得02=89.75(4L=200-32=X10-3CT011=X=10t2=10Ct1=15C73000(60.86103)2200022240267.3273000(327510)2002467.3219.610673000(1015)解得02=95.305L=250Y2=X10-3丫1=X10-3CT01=67.3273000(327510:)2解得02=99.962467.327300060.8610)300ccc73000(3275103)23000222402解得02=103.80-3®L=350丫2=X10t2=10Ct1=15C67.32-3Yi=X10(T01=2467.3273000(60.8610)350022240267.325严招—*19.610673000(1015)2467.32解得02=106.95丫2=X10-3丫1=X10-3CT01=t2=10Ct1=10C02解得73000(60.8610240202=107.66沪362.83(9}L=400丫2=X10-3t2=10Ct1=10C73000(608610)4000222402解得02=107.72327510)362467.3219.6107300067.3283r1=x10CT01=73000(105)730006083^12460-侦容(]19.61024107.7273000(1010)⑩L=450丫2=X丫1=XCT10-310-301=107.72帅严"5°19.610624107.7273000(1010)02t2=10解得73000(608610)50022402Cti=10°C02=107.72t2=10Ct1=10C107.7273000(60831］一50024107.72-3Yi=X10(T02解得73000(608610)5502107.72240202=107.7273000(608310)550'厂“6力219.61073000(1010)24107.72L=600丫2=X10-3丫1=X10-3(T01=1)L=50t2=10Ct1=10C丫1=X10-3CTY2=X10402t2=-5Ct1=15C解得02=96.3902(4)遗冰73000(524410)5067.327300J'2751?5°19.610673000(515)2467.32(2)L=100丫2=X-10-3丫1=X10-3(T01=73000(327510)1002467.32解得02=97.5373000(524410)150c“73000(327510150八“、02，673224673219.610673000(515)解得02=98.96L=200f2=x10-31=x10-(T01=t2=-5Ct1=15C73000(524410)200022402解得02=100.3673000(327510宇20067.322467.3219.610673000(515)5L=250丫2=x10-31=x10-3CT01=t2=-5Ct1=15C0273000(524410)25067.3273000(327510)25019.610673000(515)24022467.32解得02=101.59⑥L=300丫2=x10-31=x10-3CT01=t2=-5Ct1=15C73000(5244103)230002240273000(327510)3002467.3219.610673000(515)解得02=102.637)L=350丫2=x10-31=x10-3CT01=/点;番U73000?75103)2解得02解得73000(524410)362.83240267.3273000(327510)362.832467.32-619.610673000515)L=400t2=-502解得02=103.66_3Y2=X103Y1=X10-(T01=Ct1=10C73000(5244103)2400107.727300°2420202=102.13608310)4004107.7219.610673000(510)Y2=X10-3Y1=X10-3CT01=t2=-5Ct1=10C73000(524410)4500222402107.72831]24^24107.727300019.610-673000(510)解得02=100.45L=500-3Y2=X10-3丫1=X10CT01=02t2=-5Ct1=10C73000(5244103)25002402107.7273000(608310)50024107.72-619.610673000(510)解得02=99.15L=550丫2=X1=X10-3CT10-301=t2=-5Ct1=10C73000(524410竽W77?73。。。(608310/5。伯.610673000(510)02107.72550240224107.72解得02=98.15?L=600丫2=x10-3I1=x10-3CT01=t2=-5Ct1=1O°C02107.72解得240202=97.36帅(次?海19.610673000(510)(5)年均气温1)L=50Y2=X10-31=X10-3CT01=t2=15Ct1=15C67.3219.61067300025)73000(327510)56022402解得02=67.3273000(327510.2502467.32(T01=2)L=100丫2=x丫1=X10-310-3t2=15Ct1=15C67.32或^^Tgg2467.3219.610673000(135)_3Y1=x10(T01=73000(3275103215002240：解得02=67.32④L=200丫2=x10-3解得02=67.323L=150丫2=x10-3t2=15Ct1=15C67.32(327510)1000224c：(327510H5°19.610673000(135)成67.32_3Y1=x10(T01=0273000(327510)200240267.3273000(327510)2002467.3219.610673000(135)解得02=67.32L=250丫2=X10-3丫i=X10-3CT01=t2=15Cti=15C73000(327510)25002240267.327300(327510)_25G2467.3219.610673000(1515)解得02=67.326)L=300丫2=X10-3丫1=X10-3CT01=t2=15Ct1=15C0273000(327510)300240267.3273000(327510)3002467.3219.610673000(1515)解得02=67.32L=350丫2=X10-3丫1=X10-3(T01=t2=15Ct1=15C0273000(327510)3502240267.3273000(3275103)2350厂2467.3219.610673000(1515)解得02=67.32Y2=X10-31=X10-3CT01=t2=15Ct1=15C02晰(吟气03)乏举67.32E(3户响球少3仲.61q673000(155)24022467.32解得02=67.32f、3。1_=400丫2=X_3丫1=X10CT01=@L=55073000a3275)03)24002402解得02=65.80i07.7273000(60831。)竺19.610624107.72⑩L=450丫2=X10-3丫i=X10-3(T0173000(327510)450022402t2=15Cti=10C@L=500解得o2=64.20Y2=X10-373000(327510)500022422t2=15Ct1=10C解得73000(1510)107727300。(608312245024107.7219.610673000(1510)丫1=X10-3CT1077273000(6083£2-50019.610673000(1510)丫2=x丫1=x(T02他30410-3=0273000(327510}255(0107IUI.IA73000(608310}2550224107.7219.610622402t2=15Ct1=10C73000(1510)@L=600解得02=62.17Y2=X丫1=X10-3CTt2=15Ct1用0C-7300A60831.260073000(1510)□口7300a6083I]260019.610673000(327510)260024107*2202解得02=61.505、计算最高温度下的弧垂弧垂的计算公式:_3(Y1=X10)L=200L=250L=300L=350(T0=L=400L=500(T0=(T0=(T0=(T0=(T0=(T0=(T0=(T0=(T0=(T0=3232751050836.03=0.284唇751031002=爵64842.45327510/502847.66=1.932S103-竺=3.170851.66327510-32502854.70327510-33002857.03327510-33502858.83327510-3362△_q1=9.100859.23=4.677=6.460=8.524410-3-瞠=11.089859.07公10-3一型=14.083858.86327510-35002=17.43312L=550L-600f327510-35502-21.136858.59f327510-36002-25.194858.50四、作出档距与应力和弧垂的关系汇总至表4-1LGJ-150/20型导线应力弧垂计算表最低气温年均气温最大风速覆冰最周气温档距（m）应力①(MPa)应力b(MPa)应力b(MPa)应力b(MPa)应力b(MPa)弧垂f（m）50100150200250300350400450500550600五、作-10C40C的安装曲线图像（详见附录一）1、计算各温度下的应力和弧垂2平12l2E(t2t1022012」24022401应的弧垂，根据其应喔姊荷0档距弧垂1100结果如表5-110073000(32.7510)L202E73000,已知条件年均气温最大风控制区间+X温度t1(C)1510比载Y1(10-3)许用应力［bE(Mpa)应用状态方程求解各施工气象(无风、无冰、不同气温)下的安装应力，进而求得相待求条件温度t2(C)6-10010203040比载Y2(10-3)(1)L362.83(T01=,丫i=X10-3,ti=-10C,丫2=X10-3673273000(32'75103*L19.610673000(t+15)2467.32以L=50为例，t=-10，解得C02=t=0,解得C02=,t=10解得(T02一,t=20解得(T02=,t=30解得(T02=11008011002801100280110022801100228032.75100=0.5520100=0.6757100=0.8592100327510-31002=0.401102.07-31088.03t=40，解得C02=100100=1.1380(2)L362.83C01=,丫1=60,86X10-3t1=10°C,丫2=x10-32100小=0.465073000(32.7510)[50224202了乙73000?08610)l19.6106724107,72以L=400为例t=20，得C02=,ft=-10解C02=,fI100T100t=0，解得C02=,f1t=30，得C02=,f100t=40,解得C02=,ft=10，得C02=,fT1002o=1.01861100232.75101002Q74.658100=1.0733100100100=1.1280=1.1819=1.2349J=0.693温度「C）-10010档距（m）应力(T(MPa)弧垂-10Cf(m)应力(T(MPa)弧垂0Cf(m)应力(T(MPa)弧垂10Cf(m)50100150200250300350400450500550600温度「C)203040档距(m)应力(T(MPa)弧垂20Cf(m)应力(T(MPa)弧垂30Cf(m)应力(T(MPa)弧垂40Cf(m)50100150200250300350400450500550600六、做安装曲线图(见附录)七、计算说明书1、根据所在区和导线型号找出相关数据2、计算各比载，最高气温、最低气温和年均气温的比载为自重比载丫i=X10-3,24[o]j[o]i3、计算各档ljrn24(tjti)[叭r2/E(rt)2(rtr)27=X10-34、5、根据档距判断控制气象条件和临界档距，即当L＜时，年均气温为控制气La畏,ct?!而々攵最大风速比载为丫6=X10-3,遗冰比载为丫确定应力值：年均气温应力ccp=25%rp=,其他条件下的应力都为40%（r象条件；当L＞时，最大风速为控制气象条件6、E2l2列状态方程。2旦务。1旦当2402E2|22401E（t2tj以临界档距为分界点，算7、计算最高气温下，各档距所对应的弧垂工,80根据公式fE(t2tj22l2~02?2402E廿0124021求解各施工气兔列痍恩方窿各气象条件下不同档距所对应的应力值冰（丫2=X10-3）、不同气温（-10C——40C））下的安装应力，进而求得相应的弧垂，根据其应力绘制白米档距弧垂100观察档距L的弧垂可有下式进行换算附录1:■「1知■八3If■u.m』—：0iLImu■oogw—-ILJ\、no'"i乙窖物,(51.01103)2(12.16103)2