DES算法Java实现源代码

packagedes;/***加密过程：*1.初始置换IP：将明文顺序打乱重新排列，置换输出为64位。*2.将置换输出的64位明文分成左右凉拌，左一半为L0，右一半称为R0，各32位。*3。计算函数的16轮迭代。*a）第一轮加密迭代：左半边输入L0，右半边输入R0：由轮函数f实现子密钥K1对R0的加密，*结果为32位数据组f(R0,K1),*b)第二轮加密迭代：左半边输入L1=R0，右半边输入R1=L0⊕f(R0,K1),由轮函数f实现子密钥*K2对R1的加密，结果为32位数据组f(R1，K2)，f(R1,K2)与L1模2相加，得到一个32为数据组L1⊕f(R1,K2).*c)第3到16轮迭代分别用密钥K3，K4……K16进行。4.再经过逆初始置换IP-1，将数据打乱重排，生成64位密文。**子密钥生成过程：*1.将64位的密钥经过PC-1置换生成56位密钥。*2.将56位的密钥分成左右两部分，分别进行移位操作（一共进行16轮），产生16个56位长度的子密钥。*3.将16个56位的子密钥分别进行PC-2置换生成16个48位的子密钥。**轮函数f的工作过程：*1.在第i次加密迭代过程中，扩展置换E对32位的Ri-1的各位通过置换 表 关于同志近三年现实表现材料材料类招标技术评分表图表与交易pdf视力表打印pdf用图表说话 pdf 置换为48位的输出。*2.将该48位的输出与子密钥Ki进行异或操作，运算结果经过S盒代换运算，得到一个32位比特的输出。*3。该32位比特输出再经过P置换表进行P运算，将其各位打乱重排，生成32位的输出。**@authorOuyang**/publicclassDes{int[]byteKey;publicDes(int[]byteKey){this.byteKey=byteKey;}privatestaticfinalint[]IP={58,50,42,34,26,18,10,2,60,52,44,36,28,20,12,4,62,54,46,38,30,22,14,6,64,56,48,40,32,24,16,8,57,49,41,33,25,17,9,1,59,51,43,35,27,19,11,3,61,53,45,37,29,21,13,5,63,55,47,39,31,23,15,7};//64privatestaticfinalint[]IP_1={40,8,48,16,56,24,64,32,39,7,47,15,55,23,63,31,38,6,46,14,54,22,62,30,37,5,45,13,53,21,61,29,36,4,44,12,52,20,60,28,35,3,43,11,51,19,59,27,34,2,42,10,50,18,58,26,33,1,41,9,49,17,57,25};//64privatestaticfinalint[]PC_1={57,49,41,33,25,17,9,1,58,50,42,34,26,18,10,2,59,51,43,35,27,19,11,3,60,52,44,36,63,55,47,39,31,23,15,7,62,54,46,38,30,22,14,6,61,53,45,37,29,21,13,5,28,20,12,4};//56privatestaticfinalint[]PC_2={14,17,11,24,1,5,3,28,15,6,21,10,23,19,12,4,26,8,16,7,27,20,13,2,41,52,31,37,47,55,30,40,51,45,33,48,44,49,39,56,34,53,46,42,50,36,29,32};//48privatestaticfinalint[]E={32,1,2,3,4,5,4,5,6,7,8,9,8,9,10,11,12,13,12,13,14,15,16,17,16,17,18,19,20,21,20,21,22,23,24,25,24,25,26,27,28,29,28,29,30,31,32,1};//48privatestaticfinalint[]P={16,7,20,21,29,12,28,17,1,15,23,26,5,18,31,10,2,8,24,14,32,27,3,9,19,13,30,6,22,11,4,25};//32privatestaticfinalint[][][]S_Box={//S-盒{//S_Box[1]{14,4,13,1,2,15,11,8,3,10,6,12,5,9,0,7},{0,15,7,4,14,2,13,1,10,6,12,11,9,5,3,8},{4,1,14,8,13,6,2,11,15,12,9,7,3,10,5,0},{15,12,8,2,4,9,1,7,5,11,3,14,10,0,6,13}},{//S_Box[2]{15,1,8,14,6,11,3,4,9,7,2,13,12,0,5,10},{3,13,4,7,15,2,8,14,12,0,1,10,6,9,11,5},{0,14,7,11,10,4,13,1,5,8,12,6,9,3,2,15},{13,8,10,1,3,15,4,2,11,6,7,12,0,5,14,9}},{//S_Box[3]{10,0,9,14,6,3,15,5,1,13,12,7,11,4,2,8},{13,7,0,9,3,4,6,10,2,8,5,14,12,11,15,1},{13,6,4,9,8,15,3,0,11,1,2,12,5,10,14,7},{1,10,13,0,6,9,8,7,4,15,14,3,11,5,2,12}},{//S_Box[4]{7,13,14,3,0,6,9,10,1,2,8,5,11,12,4,15},{13,8,11,5,6,15,0,3,4,7,2,12,1,10,14,9},{10,6,9,0,12,11,7,13,15,1,3,14,5,2,8,4},{3,15,0,6,10,1,13,8,9,4,5,11,12,7,2,14}},{//S_Box[5]{2,12,4,1,7,10,11,6,8,5,3,15,13,0,14,9},{14,11,2,12,4,7,13,1,5,0,15,10,3,9,8,6},{4,2,1,11,10,13,7,8,15,9,12,5,6,3,0,14},{11,8,12,7,1,14,2,13,6,15,0,9,10,4,5,3}},{//S_Box[6]{12,1,10,15,9,2,6,8,0,13,3,4,14,7,5,11},{10,15,4,2,7,12,9,5,6,1,13,14,0,11,3,8},{9,14,15,5,2,8,12,3,7,0,4,10,1,13,11,6},{4,3,2,12,9,5,15,10,11,14,1,7,6,0,8,13}},{//S_Box[7]{4,11,2,14,15,0,8,13,3,12,9,7,5,10,6,1},{13,0,11,7,4,9,1,10,14,3,5,12,2,15,8,6},{1,4,11,13,12,3,7,14,10,15,6,8,0,5,9,2},{6,11,13,8,1,4,10,7,9,5,0,15,14,2,3,12}},{//S_Box[8]{13,2,8,4,6,15,11,1,10,9,3,14,5,0,12,7},{1,15,13,8,10,3,7,4,12,5,6,11,0,14,9,2},{7,11,4,1,9,12,14,2,0,6,10,13,15,3,5,8},{2,1,14,7,4,10,8,13,15,12,9,0,3,5,6,11}}};privatestaticfinalint[]LeftMove={1,1,2,2,2,2,2,2,1,2,2,2,2,2,2,1};/***对64位明文进行IP置换处理，*@paramdata需要经过初始IP置换的明文*@return64位经过置换处理的明文*/publicint[]IpReplace(int[]data){int[]ipMingWen=newint[64];for(inti=0;i 要求 对教师党员的评价套管和固井爆破片与爆破装置仓库管理基本要求三甲医院都需要复审吗 对密钥进行左移*@paramkey经过pc-1处理后的56位密钥*@return单个56位的子密钥（初步，未经过pc2置换）*/publicint[]LeftMove(int[]key,intoffset){int[]subKey=newint[56];int[]C0=newint[28];int[]D0=newint[28];int[]C1=newint[28];int[]D1=newint[28];for(inti=0;i<28;i++){C0[i]=key[i];D0[i]=key[i+28];}if(offset==1){for(inti=0;i<27;i++){C1[i]=C0[i+1];D1[i]=D0[i+1];}C1[27]=C0[0];D1[27]=D0[0];}elseif(offset==2){for(inti=0;i<26;i++){C1[i]=C0[i+2];D1[i]=D0[i+2];}C1[26]=C0[0];D1[26]=D0[0];C1[27]=C0[1];D1[27]=D0[1];}for(inti=0;i<28;i++){subKey[i]=C1[i];subKey[i+28]=D1[i];}returnsubKey;}/***根据经过PC-1置换后的56位密钥生成16个56位的子密钥。再经过PC-2置换生成16个48位的子密钥*@paramkey经过pc-1置换后的56位密钥*@return处理完全的16个48位子密钥(以二维数组的形式存储)*/publicint[][]SubKeyGenerate(int[]key){int[][]subKeyArrayTemp=newint[16][56];int[][]subKey=newint[16][48];int[]K0=newint[56];//特别注意：xxx[IP[i]-1]等类似变换//对64位的密钥进行pc-1置换变成56位的密钥for(inti=0;i<56;i++){K0[i]=key[PC_1[i]-1];//密钥进行PC-1变换}//由经过pc-1置换生成的56位密钥经过16轮左移，pc-2置换等操作生成16个48位的子密钥for(inti=0;i<16;i++){subKeyArrayTemp[i]=LeftMove(K0,LeftMove[i]);System.arraycopy(subKeyArrayTemp[i],0,K0,0,56);}for(inti=0;i<16;i++){for(intj=0;j<48;j++){subKey[i][j]=subKeyArrayTemp[i][PC_2[j]-1];}}returnsubKey;}/***对64位明文右半部分（32位）进行扩展，以进行与子密钥异或的操作*@paramdata32位的经过处理的明文*@return扩展后的48位明文*/publicint[]EExpend(int[]data){int[]dataExpend=newint[48];for(inti=0;i