二次齐次式的应用
二次齐次式的应用 ,xy?????3??
?3?i:22
axbxycy++(,,abc?u????),?????+?? ???]?????????r????/yx???i??,????????
?)???????k.?8???u?????????I??????????
??,??????????
sin
tan
cos
y?
y?
y?
=r,??????
c
e
a
=r,
????2121
()/()kyyxx=_o_o??,???3???3???i ?????+?I?????r.?)?????????s. ??1??
22
1/2
log[2()1]
xxx
yaabb=+_o+
(,)abR+
_c,????y???;????x???????y??.
?a??_?01/21,0y<<<,?H?????????O
?I,??22
2()11xxx
aabb+_o+>,?? 22
2()0xxx
aabb+_o>.8?
???i?r?(?i???????u????x
a??x
b????
?3???3?i,?8???/????2 (0)x
b>??
2
()2()10xx
aa
bb
+_o>.
???u???A????()xa b
?????3?.???i,???? ()21xa
b
>_o?k()21xa
b
<_o_o(?.??).8? ???u???A???????b???.???i,???????8
??????
a
b
??????????,?????a/1ab>,/1ab=, 0</1ab<?+??????????. ??0ab>>??,??1
a
b
>??,
log(21)a
b
x>_o;
??0ab=>??,??/1ab=??,xR_c; ??0ab<<??,??0/1ab<<??, log(21)a
b
x<_o.
??????y?=_o,?[
22
22
sin2sincoscos
4cos3sin1
y?y?y?y?
y?y?
_o_o
_o+
????????____.
?a???a?????i???a???D??4014<???n 22
sincosy?y?+,?[?????i???a???s?a???H?? ??siny??scosy??????3???3?i,???a?a??r,?a
????????2
cosy?,?[?????i?????ntany????i
??.
???i
22
22
sin2sincoscos 5cos2sin
y?y?y?y?
y?y?
_o_o
=
_o
2
2
tan2tan11
52tan18
y?y?
y?
_o_o
==
_o
.????
1
18
.
??3?????????D???I???b????,?Q???Ix
???(,???????????Q???e??????3/5??????
??????????Pr,Q?8??,??OPOQ_?,?e
4PQ=,?????????????).
?????????????)??
222222
bxayab_o=,(I)
????PQ?????)??3/5()yxc=_o,??
35
1
3
xy
c
_o
=(???D22 cab=+).(II) ????(3?)r,(3?),???????3?k
222222235 []
3
xy
bxayab
c
_o
_o=???a?? 22222
(53)()
y
abac
x
+_o
222222
215()330 y
ababbc
x
+_o=.
???/OPr,OQ??????12
,kk?????8??.?H OPOQ_??????????a??
2222
2222
33
1
53
abbc
abac
_o
=_o
+
.
?????a??2222 (3)(3)0abab_o+=,????
22
3,2baca==,?a?B????(3?)r,(3?),????
y,??22
4490xaxa+_o= ??2
41PQPQ
PQkxx==+_o
2
13/5()44PQPQ xxxxa=+_?+_o=. ???u1a=,???/2
3b=.
?????????????????)??22
/31xy_o=.
??4????????2
yx=??????O???8????
22
2tan1/2
3??
?????????QOAr,OB,???a?B??OAr,OB?? ???????a,???8?a???????k??????????C?? ???????).
?a????????AB?????)??1axby+=,?? ???????????)2
1yx_?=,???????3?k
2
()yaxbyx+=,?????a??
2
(/)(/)byxayx+_o10=,?[OAr,OB?? ????12
,kk?????8??.
???HOAOB_??????????a??11/b_o=_o, ??1b=.
???/????AB???)??1axy+=,??AB?? ????(0,1)D,???HOAr,OB????????Ar,Cr, B????,?eOCAB_?,??OCCD_?,????C?? ?????u??OD?????????a:
22
(1/2)1/4xy+_o=(0)y_?.
??5????????2222
//1xayb_o=(0a<<
)b?????Q????C,????l??(,0),(0,)ab?8??,??
???????r????l????????3/4c,?[????????
????????().
(A)2(B)3(C)2(D) 23
3
??????l?????)??//1xayb+=,
??0bxayab+_o=.
?????rl???????? 22
003
4
ab
c
ab
+_o
=
+
,
?8??????r,????b,?????a,??
4224
161630aacc_o+=, ?8???/????4
a,??
24
1616(/)3(/)0caca_o+=, ????:2
c
a
=?k
23
3
c
a
=,??
23
3
c
a
=,
?[
224
3
ca=,
22221
3
bcaa=_o=,ba<,??
?s????ab<????,?//2ca=?Q?c???i,???? 2e=,???+A.
???C??????????,ac?????3???3?i??e ????(?ke???y??)?u???????I????. ?t?????I?????D?????I
?????????????D???????;
?t???u???????+?O?i,???+???t????.?? ?????????+???s???????i??,?????????I?? ???????e?????????+??????,???.???I?e?? ?.???????????+?????????I,?I?e???<???? ?????????+???????????I.?C???H???????? ???????????????):
1?I?+?????ar,???????s?D?????I
??1?9?I?t?????????s???i:
cos()coscossinsiny?y?y?y?y?y?_o=+. ???s??????,?I
?????a?D???t??OA
uuur
r,
OB
uuur
,?sx?????t????
???a?B??y?r,y?,?[
??A?????b?u(cos,y?
sin)y?,??B?????b?u
(cos,sin)y?y?,?[
coscossinsinOAOBy?y?y?y?_?=_o uuuruuur
cos()OAOBy?y?=_?_?_o
uuuruuur
,
_?cos()coscossinsiny?y?y?y?y?y?_o=+. ?I?t???????????????,r,???;?r?????? ??????.???I?/??????????????????r,???Q?? ?a,???????a,?+???????a,???????????????? ???a??????.
2?t?????I?????????D?????I
??2???s?+???????+????????????. ???s????2,??H??P?ABC?D?HAr,B?8 ??????????????????,,,HAxHByHCz=== uuurruuururuuurr
,
?[AByx=_o
uuururr
,BCzy=_o
uuurrur
,CAxz=_o
uuurrr
,?HHA
,BCHBAC_?_?????:()0xzy_?_o=
rrur
,()yxz_?_o urrr
0=,?8?i????????:()0zxy_?_o=
rrur
,
??0zAB_o_?= ruuur
,????.
?I?t?????:?a ?????????D??????
?????????+?????9
x
y
A
O
B
A
B
2
H
C
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